# Line slope calculator 4x-3y=14

**Straight line given by points A[5; 2] and B[8; 6]**

## Calculation:

**Slope-intercept form of line:**y = 1.3333x-4.6667

**Canonical form of the line equation:**4x-3y-14 = 0

**Parametric form of the line equation:**

x = 3t+5

y = 4t+2 ; t ∈ R

**Slope:**m = 1.3333

**Slope angle of line: φ =**53°7'48″ = 0.9273 rad

**X intercept:**x

_{0}= 3.5

**Y intercept:**y

_{0}= q = -4.6667

**Distance line from the origin:**d

_{0}= 2.8

**The length of the segment AB: |AB| =**5

**Vector: AB =**(3; 4)

**Normal vector: n =**(4; -3)

**Midpoint of the segment AB: M =**[6.5; 4]

**Perpendicular Bisector equation:**3x+4y-35.5 = 0

**Vector OA = (5; 2) ; |OA| = 5.3852**

**Vector OB = (8; 6) ; |OB| = 10**

**Scalar product OA .OB = 52**

**Angle ∠ AOB = 15°4'7″ = 0.263 rad**